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# SICP exercise 2.26

From Drewiki

## Problem

Suppose we define `x` and `y` to be two lists:

(define x (list 1 2 3)) (define y (list 4 5 6))

What result is printed by the interpreter in response to evaluating each of the following expressions:

(append x y) (cons x y) (list x y)

## Solution

(append x y)

*Output:*

`
`

(1 2 3 4 5 6)

(cons x y)

*Output:*

`
`

((1 2 3) 4 5 6)

(list x y)

*Output:*

`
`

((1 2 3) (4 5 6))