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SICP exercise 2.18

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Define a procedure reverse that takes a list as argument and returns a list of the same elements in reverse order:

(reverse (list 1 4 9 16 25))


(25 16 9 4 1)


There are several ways to implement this procedure, but the easiest way is to use append. Note that the result of appending a list foo to the empty list is just the list foo.

(define nil (quote ()))
(define (reverse items)
  (if (null? items)
      (append (reverse (cdr items)) (cons (car items) nil))))


(reverse (list 1 4 9 16 25))


(25 16 9 4 1)
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