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# SICP exercise 1.35

## Problem

Show that the golden ratio <math>\phi\,</math> (see section 1.2.2 of the text) is a fixed point of the transformation <math>x \mapsto 1 + 1/x</math>, and
use this fact to compute <math>\phi\,</math> by means of the `fixed-point` procedure.

## Solution

The fixed point of the function is

<math>1 + 1/x = x\,</math>

Solving for x, we get

<math>x^2 = x + 1\,</math>

<math>x^2 - x - 1 = 0\,</math>

Using the quadratic equation to solve for *x*, we find that one of the roots of this equation is <math>\frac{1 + \sqrt{5}}{2}</math>, which is the golden ratio <math>\phi\,</math> (approximately 1.6.18).

Using the `fixed-point` procedure from the text to compute the numeric value:

(define tolerance 0.00001) (define (fixed-point f first-guess) (define (close-enough? v1 v2) (< (abs (- v1 v2)) tolerance)) (define (try guess) (let ((next (f guess))) (if (close-enough? guess next) next (try next)))) (try first-guess)) (fixed-point (lambda (x) (+ 1 (/ 1 x))) 1.0)

The result produced by Chicken Scheme 3.1 on Mac OS X 10.5 on a MacBook Pro is

`1.61803278688525`